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==Phosphorus credits== | ==Phosphorus credits== | ||
*The phosphorus credit for water that is infiltrated is 100 percent. Volume calculations are discussed above. | *The phosphorus credit for water that is infiltrated is 100 percent. Volume calculations are discussed above. | ||
− | *When an underdrain is present, phosphorus credits are a function of the position of the underdrain, media mix used, soil testing, and presence/absence of soil amendments. | + | *When an underdrain is present, water that does not infiltrate below the drain is captured by the underdrain. In this situation, phosphorus credits are a function of the position of the underdrain, media mix used, soil testing, and presence/absence of soil amendments. These are discussed below. |
===Phosphorus credit for non-volume reduction=== | ===Phosphorus credit for non-volume reduction=== |
Credits are discussed for volume, phosphorus and total suspended solids (TSS).
Volume credits for tree trenches and tree boxes includes
The following volume credits apply to individual storm events.
Water intercepted by a tree canopy may evaporate or be slowly released such that it does not contribute to stormwater runoff. An interception credit is given by a simplified value of the interception capacity (Ic), as presented by Breuer et al. (2003) for deciduous and coniferous tree species.
This credit is per storm event.
Two calculations are needed to determine the evapotranspiration (ET) credit. First is the volume of water available for ET. This equals the water stored between field capacity and the wilting point. Note this calculation is made for the entire thickness of the media regardless of whether an underdrain is present.
The second calculation is the theoretical ET. The theoretical volume of ET lost (Lindsey and Bassuk, 1991) per day is given by
\(ET = (CP) (LAI) (E_{rate}) (E_{ratio})\)
Where:
The canopy projection area (CP) is the perceived tree canopy diameter at maturity and is given by
\(CP = Π (d/2)^2\)
where d is the diameter of the canopy as measured at the dripline (feet).
CP varies by tree species. Please refer to the Tree Species List for these values. Default values can be used in place of calculating CP. Defaults for CP are based on tree size and are
The leaf area index (LAI) should be stratified by type into either
These values are based on collected research for global leaf area from 1932-2000 (Scurlock, Asner and Gower, 2002).
The evaporation rate (Erate) per unit time can be calculated using a pan evaporation rate for the given area, as available at NOAA. This should be estimated as a per day value.
The evaporation ratio (Eratio) is the equivalent that accounts for the efficiency of the leaves to transpire the available soil water or, alternately, the stomatal resistance of the canopy to transpiration and water movement. This is set at 0.20, or 20 percent based on research by Lindsey and Bassuk (1991). This means that a 1 square centimeter leaf transpires only about 1/5 as much as 1 square centimeter of pan surface.
If the soil volume is less than the recommended volume, the theoretical ET must be adjusted. Since the recommended soil volume equals 2 times the canopy project area (CP), the adjustment term is given by
\(Adjustment = (S_v)/(2 CP)\)
Where Sv is the actual soil volume in cubic feet. Multiply the theoretical ET by the adjustment term to arrive at the true value for theoretical ET.
It is recommended that calculations be based over a three day period. To determine the credit, compare the volume of water available for ET to the theoretical ET over a 3 day period. The credit is the smaller of these two values.
Recommended values for porosity, field capacity and wilting point for different soils.1
Link to this table.
Soil | Hydrologic soil group | Porosity 2 (volume/volume) | Field capacity (volume/volume) | Wilting point (volume/volume) | Porosity minus field capacity (volume/volume)3 | Field capacity minus wilting point (volume/volume)4 |
---|---|---|---|---|---|---|
Sand | A (GM, SW, or SP) | 0.43 | 0.17 | 0.025 to 0.09 | 0.26 | 0.11 |
Loamy sand | A (GM, SW, or SP) | 0.44 | 0.09 | 0.04 | 0.35 | 0.05 |
Sandy loam | A (GM, SW, or SP) | 0.45 | 0.14 | 0.05 | 0.31 | 0.09 |
Loam | B (ML or OL) | 0.47 | 0.25 to 0.32 | 0.09 to 0.15 | 0.19 | 0.16 |
Silt loam | B (ML or OL) | 0.50 | 0.28 | 0.11 | 0.22 | 0.17 |
Sandy clay loam | C | 0.4 | 0.07 | |||
Clay loam | D | 0.46 | 0.32 | 0.15 | 0.14 | 0.17 |
Silty clay loam | D | 0.47 to 0.51 | 0.30 to 0.37 | 0.17 to 0.22 | 0.16 | 0.14 |
Sandy clay | D | 0.43 | 0.11 | |||
Silty clay | D | 0.47 | 0.05 | |||
Clay | D | 0.47 | 0.32 | 0.20 | 0.15 | 0.12 |
1Sources of information include Saxton and Rawls (2006), Cornell University, USDA-NIFA, Minnesota Stormwater Manual. (See References for trees)
2Soil saturation is assumed to be equal to the porosity.
3This value may be used to represent the volume of water that will drain from a bioretention media.
4This value may be used to estimate the amount of water available for evapotranspiration
A parking lot is developed and will contain tree trenches containing red maple (Acer rubrum). The tree trench has 1000 cubic feet of sandy loam per tree.
The infiltration credit is given by
\((soil volume) (porosity - field capacity) = 1000 * 0.31 = 310 cubic feet\)
Using the tree morphology table, red maple is a large tree with a mature canopy of 30 feet. The available storage volume is given by
\(Soil volume (field capacity - wilting point) = 1000 * 0.09 = 90 cubic feet\)
The theoretical ET volume is given by
\((CP) (LAI) (E_{rate}) (E_{ratio}) (adjustment) (3 days) = 707 * 4.7 * 0.02 * 0.2 * (1000/(2 * 707)) = 28.2 cubic feet\)
The smaller value is the theoretical ET (28.2 cubic feet), so that is the volume credit. Note that if the recommended soil volume had been used the credit would be 39.9 cubic feet.
To make this calculation we used the default value of 707 for CP and the soil volume information from the table above. The evaporation rate (Erate) of 0.24 inches per day (0.02 feet per day) was from data collected at the Southwest Research and Outreach Center in Lamberton, Minnesota.
The interception credit is given by
\(707 (0.043/12) = 2.5 cubic feet\)
The division by 12 converts the calculation to feet.
The total credit is the sum of the infiltration, ET and interception credits and equals (310 + 28.2 + 2.5) or 340.7 cubic feet.
Phosphorus in soil (media) water is assumed to be 55 percent in the particulate form and 45 percent in the dissolved form.
For particulate phosphorus, the following credits apply.
For dissolved phosphorus, the following credits apply.
\(Credit = 20 (S_d / 2)\)
Where Sd is the soil depth above the underdrain, in feet.
\(Credit = 20 (S_d / 2)\)
Where Sd is the soil depth above the underdrain, in feet. Note that other soil phosphorus tests may be acceptable.
An additional phosphorus credit of 40 percent may be received if P-sorbing amendments are used. Acceptable amendments include the following.
Phosphorus credits for water entering a BMP and not infiltrating the underlying soil (i.e. going to an underdrain) are summarized in the following table.
Phosphorus credits for bioretention systems with an underdrain. This includes tree trenches and dry swales.
Link to this table
Particulate phosphorus (PP) | Dissolved phosphorus (DP) |
---|---|
Is Media Mix C or D being used or, if using a mix other than C or D, is the media phosphorus content 30 mg/kg or less per the Mehlich 3 (or equivalent) test1?
The assumption of 55 percent particulate phosphorus and 45 percent dissolved phosphorus is likely inaccurate for certain land uses, such as industrial, transportation, and some commercial areas. Studies indicate particulate phosphorus comprises a greater percent of total phosphorus in these land uses. It may therefore be appropriate to modify the above equation with locally derived ratios for particulate and dissolved phosphorus. For more information on fractionation of phosphorus in stormwater runoff, link here.
Example PP removal credit
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1. Is Media Mix C or D being used or, if using a mix other than C or D, is the media phosphorus content 30 mg/kg or less per the Mehlich 3 (or equivalent) test1?
2. Does the system include approved P-sorbing soil amendments2?
The assumption of 55 percent particulate phosphorus and 45 percent dissolved phosphorus is likely inaccurate for certain land uses, such as industrial, transportation, and some commercial areas. Studies indicate particulate phosphorus comprises a greater percent of total phosphorus in these land uses. It may therefore be appropriate to modify the above equation with locally derived ratios for particulate and dissolved phosphorus. For more information on fractionation of phosphorus in stormwater runoff, link here. |
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1Other widely accepted soil P tests may be used. Note: a basic conversion of test results may be necessary
2Acceptable P sorption amendments include